6x^2+64x=300

Solution for 6x^2+64x=300 equation:

6x^2+64x=300

We move all terms to the left:

6x^2+64x-(300)=0

a = 6; b = 64; c = -300;
Δ = b2-4ac
Δ = 642-4·6·(-300)
Δ = 11296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11296}=\sqrt{16*706}=\sqrt{16}*\sqrt{706}=4\sqrt{706}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-4\sqrt{706}}{2*6}=\frac{-64-4\sqrt{706}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+4\sqrt{706}}{2*6}=\frac{-64+4\sqrt{706}}{12}
$